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[deleted] t1_itinsqq wrote

Reply to comment by garugaga in 1956 Frigidaire Range by dezualy

[deleted]

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RespectableLurker555 t1_itiqmyg wrote

Someone needs to go back to thermodynamics class.

Electric resistive heat is 100% efficient at turning electrical energy into heat energy.

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TristanTheViking t1_itipu42 wrote

If you mean like the amount of heat that gets from the burner to the pan, sure. But that's more of a comparison you'd use between different types of burners like gas or induction, not two resistive heating elements. Heat transfer is never perfect.

If you're considering how well it converts electricity into heat, 100% is pretty accurate.

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tx001 t1_itk42cg wrote

The entire point of it is to heat a pan. That is what is generally meant by efficiency from a practical perspective. How efficient is it at getting heat into the pan?

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MSgtGunny t1_itipn9i wrote

Heat pumps have an efficiency higher than 100%.

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limpymcforskin t1_itjyczh wrote

They do because they don't generate heat. They transfer heat from one place to another. There is no possible way to generate heat at a greater efficiency than 100%

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MeshColour t1_itj9fhf wrote

I don't know of any heat pumps being used for burners, it would work but expensive initial cost for that application. Especially compared to how well induction works, and insulation on the oven increases that efficiency. Maybe for commercial kitchens, I imagine heat pump deep fryers exist?

Or someone should invent all those (and give me a small percentage of the total income from the idea)

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MSgtGunny t1_itj9z9l wrote

Oh you wouldn’t for a stove, it was just the shortest answer I could give that proves his statement as incorrect. The more complicated answer, but more relevant to his incorrect statement is that resistive heating is 100% efficient if you include electromagnetic outputs (such as infrared and visible light) as “heat”.

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limpymcforskin t1_itjyf7f wrote

There aren't any. It would take way too long. There are heat pump dryers though. Those are cool.

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