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drumsripdrummer t1_ixuuo7z wrote

You can place 52 lbs evenly spread along one half of the table, and the surface will deflect .25".


d=.142wa^4 /(E*t^3 (2.21(a/b)^3 +1))

w=1 psi

a=24 inches wide

E= 348,000 psi

t= .25 inches

b=24 inches to support


d=.142124^4 /(348000*.25^3 (2.21*1^3 +1))

d=47,112.192/17,454.375

d=2.7" @ 1 psi (or 576 lbs)

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DanielLikesPlants OP t1_ixuuvqg wrote

daaaamn thanks a ton, i think im ok sith that. maybe i can even glue it or something to the table. thanks

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drumsripdrummer t1_ixuwrf2 wrote

Good call on getting the thicker one! The 1/8" would deflect 8 times as much at the same weight. You'd be looking at about 6.5 lbs to deflect .25" with the 1/8" thickness. The polycarbonate alone is 3.1 lbs per side for 1/4" thick (and half that for half the thickness of course).

The calculation is based on 24"x24" since what's happening on one side of the table is nearly independent of the other side.

Gluing/adhering in some way will help for sure! Good luck

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