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B-F-A-K t1_ja98f2y wrote

As many said: whatever you rolled before, the next roll will always have a 1/6 chance of becoming any specifuc number. There's 6 different outcomes, each is equally likely.

I'd like to add: When figuring out the probability of the sum of multiple rolls, you look at the number of combinations that make that sum.

There's only one way to make a 2 with 2 rolls (1 and 1).

There are two ways of making a total of 3: 1+2 or 2+1

There are three ways of making a total of 4: 1+3, 3+1, 2+2

5 = 1+4, 4+1, 2+3 or 3+2

And so on.

The probability of a certain sum (12 for two sixes) is the number of combinations that give you that sum (1) divided by the total number of combinations there are (6*6), so it would be 1/36.

If you wanted another specific outcome, say the first die must be a 3 and the secomd one must be a 1, that's also 1/36. If the sum just has to be 4 the probability is 3/36 or 1/12.

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