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ComradeMicha t1_iy539u4 wrote

It generally means "how steep is the slope at this point?". The notation dy/dx can be summarized as "how much distance (d) do you go up (y) here for every bit of distance (d) you go sideways (x)?".

So if you have a gentle slope of a lush, rolling hill (or, say, a function y=0.1x+2), then you go up only a little bit when travelling sideways, in this example for every 1 unit of length sideways you only go up by 0.1 of those same units in the upwards direction, so dy/dx is 0.1/1 which is 1/10.

If, on the other hand, you have a sheer cliff of a giant mountain (or, say, y=9x-1), then for every bit you go sideways you go a lot further up, in this example 9 units up per unit sideways, so dy/dx is 9/1 which is 9.

If it's negative, that means you actually go down, not up.

Since you can easily calculate this for every known function f(x), this becomes a handy tool to find out more about that function. For example, if you want to know the maximum points (peaks) of said function, you simply have to find a point where the slope (dy/dx) first goes up (is positive), then goes down (is negative), i.e. it reaches a peak. That means you just find all the places where dy/dx is zero, and then in a second step you probe whether it went from positive to negative (maximum) or vice versa (minimum).

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Any-Growth8158 t1_iy5nbp0 wrote

You actually cannot calculate this for every known function.

Many functions have points where this will not work (e.g any non-continuous functions like the signum function, or non-smooth functions like absolute value) and some esoteric ones (like the Weierstrass function) can't be differentiated anywhere.

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TheJeeronian t1_iy5uz6w wrote

It's a pretty fun thought experiment to make up a value and pretend that this value is d(sign(x))/dx at 0, then try to run through some normal calculus with this new constant.

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