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mikesteane t1_j2dj9ac wrote

Reply to comment by antilos_weorsick in ELI5: Angles in a semicircle by [deleted]

Maybe you can't see it, but I can.

I started with a triangle in a semi-circle as requested by OP and did not assume it was a right-angled triangle. However when completing the construction as I described, it is clear (to me at least) that it can only have been a right angle to start with. I filled out a couple of extra steps to help you complete the visualisation, but it seems you need the formal algebra. Maybe OP still needs the proof, but to me it is so obvious as not to need formal proof.

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antilos_weorsick t1_j2dnhlr wrote

Ok buddy, what happens if it isn't a right triangle? Never heard of a rhombus?

Also, you keep using the words "formal algebra". I don't think they mean what you think they mean.

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mikesteane t1_j2doafd wrote

That's my point; I'm not assuming it is a right triangle, but when the construction is drawn I (even if not you) can see that it must be one. I've even given you a couple of interim steps to seeing why this is so, but you don't seem to grasp it even then.

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na3than t1_j2e5wro wrote

You ARE assuming the original triangle is a right triangle. If you take a triangle ABC, rotate it 180° and translate it so that AC coincides with the original CA, you're guaranteed to get a PARALLELOGRAM. You're only guaranteed to get a rectangle if the original triangle was a right triangle.

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