>vᵣ=rω where v is the linear speed, r is the radius of rotation and ω is the angular speed.
>For earth, r = 3950 mi, and ω = 15°/h. This gives vᵣ= 3950×15×π÷180=1034.107666 mi/h (π÷180 is just a unit conversion) at the equator. Sound familiar?
That is not explaining like I'm 5 lol, but actually a really good answer, ty.
ShesOver9k OP t1_iugx80s wrote
Reply to comment by FlyJunior172 in ELI5: if Earth rotates so fast, why does it always look still from outer space? by ShesOver9k
>vᵣ=rω where v is the linear speed, r is the radius of rotation and ω is the angular speed.
>For earth, r = 3950 mi, and ω = 15°/h. This gives vᵣ= 3950×15×π÷180=1034.107666 mi/h (π÷180 is just a unit conversion) at the equator. Sound familiar?
That is not explaining like I'm 5 lol, but actually a really good answer, ty.